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x+26-8x=4x(2-x)
We move all terms to the left:
x+26-8x-(4x(2-x))=0
We add all the numbers together, and all the variables
x-8x-(4x(-1x+2))+26=0
We add all the numbers together, and all the variables
-7x-(4x(-1x+2))+26=0
We calculate terms in parentheses: -(4x(-1x+2)), so:We get rid of parentheses
4x(-1x+2)
We multiply parentheses
-4x^2+8x
Back to the equation:
-(-4x^2+8x)
4x^2-8x-7x+26=0
We add all the numbers together, and all the variables
4x^2-15x+26=0
a = 4; b = -15; c = +26;
Δ = b2-4ac
Δ = -152-4·4·26
Δ = -191
Delta is less than zero, so there is no solution for the equation
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