x+2=(4/9)(2x+1)

Solution for x+2=(4/9)(2x+1) equation:

x+2=(4/9)(2x+1)

We move all terms to the left:

x+2-((4/9)(2x+1))=0


Domain of the equation: 9)(2x+1))!=0

x∈R


We add all the numbers together, and all the variables

x-((+4/9)(2x+1))+2=0

We multiply parentheses ..

-((+8x^2+4/9*1))+x+2=0

We multiply all the terms by the denominator


-((+8x^2+4+x*9*1))+2*9*1))=0


We calculate terms in parentheses: -((+8x^2+4+x*9*1)), so:

(+8x^2+4+x*9*1)

We get rid of parentheses

8x^2+x*9*1+4

Wy multiply elements

8x^2+9x*1+4

Wy multiply elements

8x^2+9x+4

Back to the equation:

-(8x^2+9x+4)


We add all the numbers together, and all the variables

-(8x^2+9x+4)=0

We get rid of parentheses

-8x^2-9x-4=0

a = -8; b = -9; c = -4;
Δ = b2-4ac
Δ = -92-4·(-8)·(-4)
Δ = -47
Delta is less than zero, so there is no solution for the equation