x+2=-1/3x-2

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Solution for x+2=-1/3x-2 equation:



x+2=-1/3x-2
We move all terms to the left:
x+2-(-1/3x-2)=0
Domain of the equation: 3x-2)!=0
x∈R
We get rid of parentheses
x+1/3x+2+2=0
We multiply all the terms by the denominator
x*3x+2*3x+2*3x+1=0
Wy multiply elements
3x^2+6x+6x+1=0
We add all the numbers together, and all the variables
3x^2+12x+1=0
a = 3; b = 12; c = +1;
Δ = b2-4ac
Δ = 122-4·3·1
Δ = 132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{132}=\sqrt{4*33}=\sqrt{4}*\sqrt{33}=2\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{33}}{2*3}=\frac{-12-2\sqrt{33}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{33}}{2*3}=\frac{-12+2\sqrt{33}}{6} $

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