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x+2=5/x
We move all terms to the left:
x+2-(5/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+5/x)+2=0
We get rid of parentheses
x-5/x+2=0
We multiply all the terms by the denominator
x*x+2*x-5=0
We add all the numbers together, and all the variables
2x+x*x-5=0
Wy multiply elements
x^2+2x-5=0
a = 1; b = 2; c = -5;
Δ = b2-4ac
Δ = 22-4·1·(-5)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{6}}{2*1}=\frac{-2-2\sqrt{6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{6}}{2*1}=\frac{-2+2\sqrt{6}}{2} $
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