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x+2=x2+3
We move all terms to the left:
x+2-(x2+3)=0
We add all the numbers together, and all the variables
-(+x^2+3)+x+2=0
We get rid of parentheses
-x^2+x-3+2=0
We add all the numbers together, and all the variables
-1x^2+x-1=0
a = -1; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-1)·(-1)
Δ = -3
Delta is less than zero, so there is no solution for the equation
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