x+2x+60+(x+30)+(x-10)+(x+40)=(6-2)180

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Solution for x+2x+60+(x+30)+(x-10)+(x+40)=(6-2)180 equation: 



x+2x+60+(x+30)+(x-10)+(x+40)=(6-2)180

We move all terms to the left:

x+2x+60+(x+30)+(x-10)+(x+40)-((6-2)180)=0

We add all the numbers together, and all the variables

x+2x+(x+30)+(x-10)+(x+40)+60-(4180)=0

We add all the numbers together, and all the variables

3x+(x+30)+(x-10)+(x+40)-4120=0

We get rid of parentheses

3x+x+x+x+30-10+40-4120=0

We add all the numbers together, and all the variables

6x-4060=0

We move all terms containing x to the left, all other terms to the right

6x=4060

x=4060/6

x=676+2/3

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