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x+2x-(x+3)=x-(x-5)
We move all terms to the left:
x+2x-(x+3)-(x-(x-5))=0
We add all the numbers together, and all the variables
3x-(x+3)-(x-(x-5))=0
We get rid of parentheses
3x-x-(x-(x-5))-3=0
We calculate terms in parentheses: -(x-(x-5)), so:We add all the numbers together, and all the variables
x-(x-5)
We get rid of parentheses
x-x+5
We add all the numbers together, and all the variables
5
Back to the equation:
-(5)
2x-8=0
We move all terms containing x to the left, all other terms to the right
2x=8
x=8/2
x=4
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