x+2y=10;2x+4y=28

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Remember to put linear equations with variables x and y.
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2x+y=8
x+3y=14

Solution for x+2y=10;2x+4y=28 system of equations: 


  • /| x+2*y-10 = 0| 2*x+4*y-28 = 0
  • We try to solve the equation: x+2*y-10 = 0
  • x+2*y-10 = 0 // - x-10
  • 2*y = -(x-10) // : 2
  • y = (-(x-10))/2
  • y = (10-x)/2
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 4*((10-x)/2)+2*x-28 = 0| y = (10-x)/2
  • (4*(10-x))/2+2*x-28 = 0
  • 20-28 = 0
  • -8 = 0
  • -8 = 0
  • x belongs to the empty set
  • The system of equations does not have any solution

 

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