x+2y=4;-10x-4y=20

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2x+y=8
x+3y=14

Solution for x+2y=4;-10x-4y=20 system of equations: 


  • /| x+2*y-4 = 0| -10*x-(4*y)-20 = 0
  • We try to solve the equation: x+2*y-4 = 0
  • x+2*y-4 = 0 // - x-4
  • 2*y = -(x-4) // : 2
  • y = (-(x-4))/2
  • y = (4-x)/2
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| -(4*((4-x)/2))-10*x-20 = 0| y = (4-x)/2
  • (-1*4*(4-x))/2-10*x-20 = 0
  • -8*x-20-8 = 0
  • -8*x-28 = 0
  • -8*x-28 = 0 // + 28
  • -8*x = 28 // : -8
  • x = 28/(-8)
  • x = -7/2
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (4-x)/2: 
  • y = (7/2+4)/2
  • y = 15/2/2
  • y = 15/4
  • We get a system of equations:
  • /| y = 15/4| x = -7/2

 

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