x+2y=5;2x+4y=10

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Solution for x+2y=5;2x+4y=10 system of equations: 


  • /| x+2*y-5 = 0| 2*x+4*y-10 = 0
  • We try to solve the equation: x+2*y-5 = 0
  • x+2*y-5 = 0 // - x-5
  • 2*y = -(x-5) // : 2
  • y = (-(x-5))/2
  • y = (5-x)/2
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 4*((5-x)/2)+2*x-10 = 0| y = (5-x)/2
  • (4*(5-x))/2+2*x-10 = 0
  • 10-10 = 0
  • 0 = 0
  • The system of equations has infinitely many solutions

 

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