x+3(1-2x)-4=6x+2(x+3)

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Solution for x+3(1-2x)-4=6x+2(x+3) equation: 



x+3(1-2x)-4=6x+2(x+3)

We move all terms to the left:

x+3(1-2x)-4-(6x+2(x+3))=0

We add all the numbers together, and all the variables

x+3(-2x+1)-(6x+2(x+3))-4=0

We multiply parentheses

x-6x-(6x+2(x+3))+3-4=0



We calculate terms in parentheses: -(6x+2(x+3)), so:

6x+2(x+3)

We multiply parentheses

6x+2x+6

We add all the numbers together, and all the variables

8x+6

Back to the equation:

-(8x+6)



We add all the numbers together, and all the variables

-5x-(8x+6)-1=0

We get rid of parentheses

-5x-8x-6-1=0

We add all the numbers together, and all the variables

-13x-7=0

We move all terms containing x to the left, all other terms to the right

-13x=7

x=7/-13

x=-7/13

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