x+3(2x+1)=4x-5(x-3)

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Solution for x+3(2x+1)=4x-5(x-3) equation: 



x+3(2x+1)=4x-5(x-3)

We move all terms to the left:

x+3(2x+1)-(4x-5(x-3))=0

We multiply parentheses

x+6x-(4x-5(x-3))+3=0



We calculate terms in parentheses: -(4x-5(x-3)), so:

4x-5(x-3)

We multiply parentheses

4x-5x+15

We add all the numbers together, and all the variables

-1x+15

Back to the equation:

-(-1x+15)



We add all the numbers together, and all the variables

7x-(-1x+15)+3=0

We get rid of parentheses

7x+1x-15+3=0

We add all the numbers together, and all the variables

8x-12=0

We move all terms containing x to the left, all other terms to the right

8x=12

x=12/8

x=1+1/2

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