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x+3(x+1)=(x-8)
We move all terms to the left:
x+3(x+1)-((x-8))=0
We multiply parentheses
x+3x-((x-8))+3=0
We calculate terms in parentheses: -((x-8)), so:We add all the numbers together, and all the variables
(x-8)
We get rid of parentheses
x-8
Back to the equation:
-(x-8)
4x-(x-8)+3=0
We get rid of parentheses
4x-x+8+3=0
We add all the numbers together, and all the variables
3x+11=0
We move all terms containing x to the left, all other terms to the right
3x=-11
x=-11/3
x=-3+2/3
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