x+3(x+2)=2(x+1)+20

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Solution for x+3(x+2)=2(x+1)+20 equation:


Simplifying
x + 3(x + 2) = 2(x + 1) + 20

Reorder the terms:
x + 3(2 + x) = 2(x + 1) + 20
x + (2 * 3 + x * 3) = 2(x + 1) + 20
x + (6 + 3x) = 2(x + 1) + 20

Reorder the terms:
6 + x + 3x = 2(x + 1) + 20

Combine like terms: x + 3x = 4x
6 + 4x = 2(x + 1) + 20

Reorder the terms:
6 + 4x = 2(1 + x) + 20
6 + 4x = (1 * 2 + x * 2) + 20
6 + 4x = (2 + 2x) + 20

Reorder the terms:
6 + 4x = 2 + 20 + 2x

Combine like terms: 2 + 20 = 22
6 + 4x = 22 + 2x

Solving
6 + 4x = 22 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
6 + 4x + -2x = 22 + 2x + -2x

Combine like terms: 4x + -2x = 2x
6 + 2x = 22 + 2x + -2x

Combine like terms: 2x + -2x = 0
6 + 2x = 22 + 0
6 + 2x = 22

Add '-6' to each side of the equation.
6 + -6 + 2x = 22 + -6

Combine like terms: 6 + -6 = 0
0 + 2x = 22 + -6
2x = 22 + -6

Combine like terms: 22 + -6 = 16
2x = 16

Divide each side by '2'.
x = 8

Simplifying
x = 8

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