x+3+(9+x)+(-3)=x+3+(-3)+(9+x)

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Solution for x+3+(9+x)+(-3)=x+3+(-3)+(9+x) equation: 



x+3+(9+x)+(-3)=x+3+(-3)+(9+x)

We move all terms to the left:

x+3+(9+x)+(-3)-(x+3+(-3)+(9+x))=0

We add all the numbers together, and all the variables

x+(x+9)-(x+3+(-3)+(x+9))+3+(-3)=0

We add all the numbers together, and all the variables

x+(x+9)-(x+3+(-3)+(x+9))=0

We get rid of parentheses

x+x-(x+3+(-3)+(x+9))+9=0



We calculate terms in parentheses: -(x+3+(-3)+(x+9)), so:

x+3+(-3)+(x+9)

determiningTheFunctionDomain
x+(x+9)+3+(-3)

We add all the numbers together, and all the variables

x+(x+9)

We get rid of parentheses

x+x+9

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We add all the numbers together, and all the variables

2x-(2x+9)+9=0

We get rid of parentheses

2x-2x-9+9=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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