x+3+3=-(x+4)+(3x-2)

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Solution for x+3+3=-(x+4)+(3x-2) equation: 



x+3+3=-(x+4)+(3x-2)

We move all terms to the left:

x+3+3-(-(x+4)+(3x-2))=0

We add all the numbers together, and all the variables

x-(-(x+4)+(3x-2))+6=0



We calculate terms in parentheses: -(-(x+4)+(3x-2)), so:

-(x+4)+(3x-2)

We get rid of parentheses

-x+3x-4-2

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

x-2x+6+6=0

We add all the numbers together, and all the variables

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12

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