x+3+x+3=-(x+4)+)+(3x-2)

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Solution for x+3+x+3=-(x+4)+)+(3x-2) equation: 



x+3+x+3=-(x+4)+)+(3x-2)

We move all terms to the left:

x+3+x+3-(-(x+4)+)+(3x-2))=0

We add all the numbers together, and all the variables

2x-(-(x+4)+)+(3x-2))+3+3=0



We calculate terms in parentheses: -(-(x+4)+), so:

-(x+4)+

We add all the numbers together, and all the variables

-(x+4)

We get rid of parentheses

-x-4

We add all the numbers together, and all the variables

-1x-4

Back to the equation:

-(-1x-4)



We get rid of parentheses

2x+1x+(3x-2))+3+3+4=0

We add all the numbers together, and all the variables

3x+(3x-2))+3+3+4=0

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