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x+3+x+3=-(x+4)+)+(3x-2)
We move all terms to the left:
x+3+x+3-(-(x+4)+)+(3x-2))=0
We add all the numbers together, and all the variables
2x-(-(x+4)+)+(3x-2))+3+3=0
We calculate terms in parentheses: -(-(x+4)+), so:We get rid of parentheses
-(x+4)+
We add all the numbers together, and all the variables
-(x+4)
We get rid of parentheses
-x-4
We add all the numbers together, and all the variables
-1x-4
Back to the equation:
-(-1x-4)
2x+1x+(3x-2))+3+3+4=0
We add all the numbers together, and all the variables
3x+(3x-2))+3+3+4=0
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