x+3+x+3=-(x+4)+4(3x-2)

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Solution for x+3+x+3=-(x+4)+4(3x-2) equation: 



x+3+x+3=-(x+4)+4(3x-2)

We move all terms to the left:

x+3+x+3-(-(x+4)+4(3x-2))=0

We add all the numbers together, and all the variables

2x-(-(x+4)+4(3x-2))+6=0



We calculate terms in parentheses: -(-(x+4)+4(3x-2)), so:

-(x+4)+4(3x-2)

We multiply parentheses

-(x+4)+12x-8

We get rid of parentheses

-x+12x-4-8

We add all the numbers together, and all the variables

11x-12

Back to the equation:

-(11x-12)



We get rid of parentheses

2x-11x+12+6=0

We add all the numbers together, and all the variables

-9x+18=0

We move all terms containing x to the left, all other terms to the right

-9x=-18

x=-18/-9

x=+2

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