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x+3+x+3=-(x+4)+x-2
We move all terms to the left:
x+3+x+3-(-(x+4)+x-2)=0
We add all the numbers together, and all the variables
2x-(-(x+4)+x-2)+6=0
We calculate terms in parentheses: -(-(x+4)+x-2), so:We add all the numbers together, and all the variables
-(x+4)+x-2
We add all the numbers together, and all the variables
x-(x+4)-2
We get rid of parentheses
x-x-4-2
We add all the numbers together, and all the variables
-6
Back to the equation:
-(-6)
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6
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