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x+3+x+3=4x-(2x-5)
We move all terms to the left:
x+3+x+3-(4x-(2x-5))=0
We add all the numbers together, and all the variables
2x-(4x-(2x-5))+6=0
We calculate terms in parentheses: -(4x-(2x-5)), so:We get rid of parentheses
4x-(2x-5)
We get rid of parentheses
4x-2x+5
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
2x-2x-5+6=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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