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x+3-(2x-4)=4+2(3x-1)
We move all terms to the left:
x+3-(2x-4)-(4+2(3x-1))=0
We get rid of parentheses
x-2x-(4+2(3x-1))+4+3=0
We calculate terms in parentheses: -(4+2(3x-1)), so:We add all the numbers together, and all the variables
4+2(3x-1)
determiningTheFunctionDomain 2(3x-1)+4
We multiply parentheses
6x-2+4
We add all the numbers together, and all the variables
6x+2
Back to the equation:
-(6x+2)
-1x-(6x+2)+7=0
We get rid of parentheses
-1x-6x-2+7=0
We add all the numbers together, and all the variables
-7x+5=0
We move all terms containing x to the left, all other terms to the right
-7x=-5
x=-5/-7
x=5/7
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