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x+3-(4/x-1)=5
We move all terms to the left:
x+3-(4/x-1)-(5)=0
Domain of the equation: x-1)!=0We add all the numbers together, and all the variables
x∈R
x-(4/x-1)-2=0
We get rid of parentheses
x-4/x+1-2=0
We multiply all the terms by the denominator
x*x+1*x-2*x-4=0
We add all the numbers together, and all the variables
-1x+x*x-4=0
Wy multiply elements
x^2-1x-4=0
a = 1; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·1·(-4)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{17}}{2*1}=\frac{1-\sqrt{17}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{17}}{2*1}=\frac{1+\sqrt{17}}{2} $
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