x+3-x=x2+12+x+3-x=4(x2+12)

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Solution for x+3-x=x2+12+x+3-x=4(x2+12) equation: 



x+3-x=x2+12+x+3-x=4(x2+12)

We move all terms to the left:

x+3-x-(x2+12+x+3-x)=0

We add all the numbers together, and all the variables

-(+x^2+12+3)+x-x+3=0

We add all the numbers together, and all the variables

-(+x^2+12+3)+3=0

We get rid of parentheses

-x^2-12-3+3=0

We add all the numbers together, and all the variables

-1x^2-12=0

a = -1; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·(-1)·(-12)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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