x+3/(x)x-1=4x-2/7x+2

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Solution for x+3/(x)x-1=4x-2/7x+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+(3/x)*x-1 = 4*x-((2/7)*x)+2 // - 4*x-((2/7)*x)+2

x-(4*x)+(2/7)*x+(3/x)*x-2-1 = 0

x-4*x+(2/7)*x+(3/x)*x-2-1 = 0

-19/7*x = 0 // : -19/7

x = 0

x in { 0} 

x belongs to the empty set

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