x+3/3x+2=-2

Solution for x+3/3x+2=-2 equation:

x+3/3x+2=-2

We move all terms to the left:

x+3/3x+2-(-2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

x+3/3x+4=0

We multiply all the terms by the denominator


x*3x+4*3x+3=0

Wy multiply elements

3x^2+12x+3=0

a = 3; b = 12; c = +3;
Δ = b2-4ac
Δ = 122-4·3·3
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-6\sqrt{3}}{2*3}=\frac{-12-6\sqrt{3}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+6\sqrt{3}}{2*3}=\frac{-12+6\sqrt{3}}{6}
$