x+3/x+6=x+3/x+2

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Solution for x+3/x+6=x+3/x+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+3/x+6 = x+3/x+2 // - x+3/x+2

x-x+3/x-(3/x)-2+6 = 0

x-x+3/x-3*x^-1-2+6 = 0

4 = 0

x belongs to the empty set

x belongs to the empty set

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