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x+3/x-3+6(x-3/x+3)=5
We move all terms to the left:
x+3/x-3+6(x-3/x+3)-(5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x+3)!=0We add all the numbers together, and all the variables
x∈R
x+3/x+6(x-3/x+3)-8=0
We multiply parentheses
x+3/x+6x-18x+18-8=0
We multiply all the terms by the denominator
x*x+6x*x-18x*x+18*x-8*x+3=0
We add all the numbers together, and all the variables
10x+x*x+6x*x-18x*x+3=0
Wy multiply elements
x^2+6x^2-18x^2+10x+3=0
We add all the numbers together, and all the variables
-11x^2+10x+3=0
a = -11; b = 10; c = +3;
Δ = b2-4ac
Δ = 102-4·(-11)·3
Δ = 232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{232}=\sqrt{4*58}=\sqrt{4}*\sqrt{58}=2\sqrt{58}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{58}}{2*-11}=\frac{-10-2\sqrt{58}}{-22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{58}}{2*-11}=\frac{-10+2\sqrt{58}}{-22} $
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