x+30+x+(3/5)x+(2/5)x=360

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Solution for x+30+x+(3/5)x+(2/5)x=360 equation:



x+30+x+(3/5)x+(2/5)x=360
We move all terms to the left:
x+30+x+(3/5)x+(2/5)x-(360)=0
Domain of the equation: 5)x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x+x+(+3/5)x+(+2/5)x+30-360=0
We add all the numbers together, and all the variables
2x+(+3/5)x+(+2/5)x-330=0
We multiply parentheses
3x^2+2x^2+2x-330=0
We add all the numbers together, and all the variables
5x^2+2x-330=0
a = 5; b = 2; c = -330;
Δ = b2-4ac
Δ = 22-4·5·(-330)
Δ = 6604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6604}=\sqrt{4*1651}=\sqrt{4}*\sqrt{1651}=2\sqrt{1651}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1651}}{2*5}=\frac{-2-2\sqrt{1651}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1651}}{2*5}=\frac{-2+2\sqrt{1651}}{10} $

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