x+30+x+(3/5)x+(2/5)x=360

Solution for x+30+x+(3/5)x+(2/5)x=360 equation:

x+30+x+(3/5)x+(2/5)x=360

We move all terms to the left:

x+30+x+(3/5)x+(2/5)x-(360)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+x+(+3/5)x+(+2/5)x+30-360=0

We add all the numbers together, and all the variables

2x+(+3/5)x+(+2/5)x-330=0

We multiply parentheses

3x^2+2x^2+2x-330=0

We add all the numbers together, and all the variables

5x^2+2x-330=0

a = 5; b = 2; c = -330;
Δ = b2-4ac
Δ = 22-4·5·(-330)
Δ = 6604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6604}=\sqrt{4*1651}=\sqrt{4}*\sqrt{1651}=2\sqrt{1651}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1651}}{2*5}=\frac{-2-2\sqrt{1651}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1651}}{2*5}=\frac{-2+2\sqrt{1651}}{10}
$