x+36-x-25=x2+x-6-20

Solution for x+36-x-25=x2+x-6-20 equation:

x+36-x-25=x2+x-6-20

We move all terms to the left:

x+36-x-25-(x2+x-6-20)=0

We add all the numbers together, and all the variables

-(+x^2+x-6-20)+x-x+36-25=0

We add all the numbers together, and all the variables

-(+x^2+x-6-20)+11=0

We get rid of parentheses

-x^2-x+6+20+11=0

We add all the numbers together, and all the variables

-1x^2-1x+37=0

a = -1; b = -1; c = +37;
Δ = b2-4ac
Δ = -12-4·(-1)·37
Δ = 149
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{149}}{2*-1}=\frac{1-\sqrt{149}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{149}}{2*-1}=\frac{1+\sqrt{149}}{-2}
$