x+3=(3/2x)+2

Solution for x+3=(3/2x)+2 equation:

x+3=(3/2x)+2

We move all terms to the left:

x+3-((3/2x)+2)=0


Domain of the equation: 2x)+2)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-((+3/2x)+2)+3=0

We multiply all the terms by the denominator


x*2x)+2)-((+3*2x)+2)+3=0

Wy multiply elements

2x^2+6x=0

a = 2; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·2·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*2}=\frac{-12}{4}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*2}=\frac{0}{4}
=0
$