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x+3=-(3)/(2)(-3x+5)
We move all terms to the left:
x+3-(-(3)/(2)(-3x+5))=0
Domain of the equation: 2(-3x+5))!=0We multiply all the terms by the denominator
x∈R
x*2(-3x+5))-(+3*2(-3x+5))-3=0
Wy multiply elements
2x^2(-+6x(-=0
We use the square of the difference formula
2x^2(-6x(-=0
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