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x+3=-2/5x-11
We move all terms to the left:
x+3-(-2/5x-11)=0
Domain of the equation: 5x-11)!=0We get rid of parentheses
x∈R
x+2/5x+11+3=0
We multiply all the terms by the denominator
x*5x+11*5x+3*5x+2=0
Wy multiply elements
5x^2+55x+15x+2=0
We add all the numbers together, and all the variables
5x^2+70x+2=0
a = 5; b = 70; c = +2;
Δ = b2-4ac
Δ = 702-4·5·2
Δ = 4860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4860}=\sqrt{324*15}=\sqrt{324}*\sqrt{15}=18\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-18\sqrt{15}}{2*5}=\frac{-70-18\sqrt{15}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+18\sqrt{15}}{2*5}=\frac{-70+18\sqrt{15}}{10} $
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