x+3=1/4x+6

Solution for x+3=1/4x+6 equation:

x+3=1/4x+6

We move all terms to the left:

x+3-(1/4x+6)=0


Domain of the equation: 4x+6)!=0

x∈R


We get rid of parentheses

x-1/4x-6+3=0

We multiply all the terms by the denominator


x*4x-6*4x+3*4x-1=0

Wy multiply elements

4x^2-24x+12x-1=0

We add all the numbers together, and all the variables

4x^2-12x-1=0

a = 4; b = -12; c = -1;
Δ = b2-4ac
Δ = -122-4·4·(-1)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{10}}{2*4}=\frac{12-4\sqrt{10}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{10}}{2*4}=\frac{12+4\sqrt{10}}{8}
$