x+3x+(3x-200)=1550

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Solution for x+3x+(3x-200)=1550 equation: 



x+3x+(3x-200)=1550

We move all terms to the left:

x+3x+(3x-200)-(1550)=0

We add all the numbers together, and all the variables

4x+(3x-200)-1550=0

We get rid of parentheses

4x+3x-200-1550=0

We add all the numbers together, and all the variables

7x-1750=0

We move all terms containing x to the left, all other terms to the right

7x=1750

x=1750/7

x=250

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