x+3x+(x+6)=(x-4)+(x-4)=40

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Solution for x+3x+(x+6)=(x-4)+(x-4)=40 equation: 



x+3x+(x+6)=(x-4)+(x-4)=40

We move all terms to the left:

x+3x+(x+6)-((x-4)+(x-4))=0

We add all the numbers together, and all the variables

4x+(x+6)-((x-4)+(x-4))=0

We get rid of parentheses

4x+x-((x-4)+(x-4))+6=0



We calculate terms in parentheses: -((x-4)+(x-4)), so:

(x-4)+(x-4)

We get rid of parentheses

x+x-4-4

We add all the numbers together, and all the variables

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

5x-(2x-8)+6=0

We get rid of parentheses

5x-2x+8+6=0

We add all the numbers together, and all the variables

3x+14=0

We move all terms containing x to the left, all other terms to the right

3x=-14

x=-14/3

x=-4+2/3

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