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x+3x+2=x2+x-10
We move all terms to the left:
x+3x+2-(x2+x-10)=0
We add all the numbers together, and all the variables
-(+x^2+x-10)+x+3x+2=0
We add all the numbers together, and all the variables
-(+x^2+x-10)+4x+2=0
We get rid of parentheses
-x^2-x+4x+10+2=0
We add all the numbers together, and all the variables
-1x^2+3x+12=0
a = -1; b = 3; c = +12;
Δ = b2-4ac
Δ = 32-4·(-1)·12
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{57}}{2*-1}=\frac{-3-\sqrt{57}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{57}}{2*-1}=\frac{-3+\sqrt{57}}{-2} $
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