x+3x+2=x2+x-10

Solution for x+3x+2=x2+x-10 equation:

x+3x+2=x2+x-10

We move all terms to the left:

x+3x+2-(x2+x-10)=0

We add all the numbers together, and all the variables

-(+x^2+x-10)+x+3x+2=0

We add all the numbers together, and all the variables

-(+x^2+x-10)+4x+2=0

We get rid of parentheses

-x^2-x+4x+10+2=0

We add all the numbers together, and all the variables

-1x^2+3x+12=0

a = -1; b = 3; c = +12;
Δ = b2-4ac
Δ = 32-4·(-1)·12
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{57}}{2*-1}=\frac{-3-\sqrt{57}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{57}}{2*-1}=\frac{-3+\sqrt{57}}{-2}
$