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x+3x+2x+3x(x+1)=30
We move all terms to the left:
x+3x+2x+3x(x+1)-(30)=0
We add all the numbers together, and all the variables
6x+3x(x+1)-30=0
We multiply parentheses
3x^2+6x+3x-30=0
We add all the numbers together, and all the variables
3x^2+9x-30=0
a = 3; b = 9; c = -30;
Δ = b2-4ac
Δ = 92-4·3·(-30)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-21}{2*3}=\frac{-30}{6} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+21}{2*3}=\frac{12}{6} =2 $
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