x+3x+x+3=-(x+4)+(3x-2)

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Solution for x+3x+x+3=-(x+4)+(3x-2) equation: 



x+3x+x+3=-(x+4)+(3x-2)

We move all terms to the left:

x+3x+x+3-(-(x+4)+(3x-2))=0

We add all the numbers together, and all the variables

5x-(-(x+4)+(3x-2))+3=0



We calculate terms in parentheses: -(-(x+4)+(3x-2)), so:

-(x+4)+(3x-2)

We get rid of parentheses

-x+3x-4-2

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

5x-2x+6+3=0

We add all the numbers together, and all the variables

3x+9=0

We move all terms containing x to the left, all other terms to the right

3x=-9

x=-9/3

x=-3

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