If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x+4(1/4)x=8
We move all terms to the left:
x+4(1/4)x-(8)=0
Domain of the equation: 4)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x+4(+1/4)x-8=0
We multiply parentheses
4x^2+x-8=0
a = 4; b = 1; c = -8;
Δ = b2-4ac
Δ = 12-4·4·(-8)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{129}}{2*4}=\frac{-1-\sqrt{129}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{129}}{2*4}=\frac{-1+\sqrt{129}}{8} $
| 6b+2b=20 | | 3/4K+5(k-6)=2 | | (4d+3)(d+6)=0 | | 9-3x=6x-24 | | 4(3^x+1)-3^2x=27 | | (7t-2)-(-3+1)=-3+9t | | 18m-10m=16 | | 11(v+2)-2v=3(3v+2)-8 | | -6x-6=-78 | | 2x+4x=3-3 | | 2x+3/5x=3 | | -18=9y+10 | | 4(x-1)-5x=-(2x-3) | | 12=90/x | | 2(-7/2+m)+3=4(m-3)+11/2 | | 5x-3=2(2x+3)-3 | | x+1÷4-2=3 | | 2(-41/2+3=4(m-3)+51/2 | | -3m(2m-7)=0 | | x+1/4-2=3 | | -43=-y|3 | | Y+y/2=900 | | x-7+x=85 | | x^2+x9-36=0 | | a-2.01=5.5 | | s+49=3s+11 | | 1/4(4t-7)=t+7/8 | | t+44=2t+26 | | 5/x+4-7/x-4=12/x^2-16 | | -3(x+6)=-36 | | 4(b-2)=-4b-8(5+b) | | 10c=13.71 |