x+4(x-2)-3(x-4)=4(x-3)

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Solution for x+4(x-2)-3(x-4)=4(x-3) equation: 



x+4(x-2)-3(x-4)=4(x-3)

We move all terms to the left:

x+4(x-2)-3(x-4)-(4(x-3))=0

We multiply parentheses

x+4x-3x-(4(x-3))-8+12=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

2x-(4x-12)+4=0

We get rid of parentheses

2x-4x+12+4=0

We add all the numbers together, and all the variables

-2x+16=0

We move all terms containing x to the left, all other terms to the right

-2x=-16

x=-16/-2

x=+8

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