x+4+3x-8=6(x+2)

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Solution for x+4+3x-8=6(x+2) equation: 



x+4+3x-8=6(x+2)

We move all terms to the left:

x+4+3x-8-(6(x+2))=0

We add all the numbers together, and all the variables

4x-(6(x+2))-4=0



We calculate terms in parentheses: -(6(x+2)), so:

6(x+2)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

4x-6x-12-4=0

We add all the numbers together, and all the variables

-2x-16=0

We move all terms containing x to the left, all other terms to the right

-2x=16

x=16/-2

x=-8

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