x+4-2(-6x-1)=3(x-4)

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Solution for x+4-2(-6x-1)=3(x-4) equation:



x+4-2(-6x-1)=3(x-4)
We move all terms to the left:
x+4-2(-6x-1)-(3(x-4))=0
We multiply parentheses
x+12x-(3(x-4))+2+4=0
We calculate terms in parentheses: -(3(x-4)), so:
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
We add all the numbers together, and all the variables
13x-(3x-12)+6=0
We get rid of parentheses
13x-3x+12+6=0
We add all the numbers together, and all the variables
10x+18=0
We move all terms containing x to the left, all other terms to the right
10x=-18
x=-18/10
x=-1+4/5

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