x+4-2=3/7x=7

Solution for x+4-2=3/7x=7 equation:

x+4-2=3/7x=7

We move all terms to the left:

x+4-2-(3/7x)=0


Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-(+3/7x)+4-2=0

We add all the numbers together, and all the variables

x-(+3/7x)+2=0

We get rid of parentheses

x-3/7x+2=0

We multiply all the terms by the denominator


x*7x+2*7x-3=0

Wy multiply elements

7x^2+14x-3=0

a = 7; b = 14; c = -3;
Δ = b2-4ac
Δ = 142-4·7·(-3)
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{70}}{2*7}=\frac{-14-2\sqrt{70}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{70}}{2*7}=\frac{-14+2\sqrt{70}}{14}
$