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x+4/x-3=6
We move all terms to the left:
x+4/x-3-(6)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
x+4/x-9=0
We multiply all the terms by the denominator
x*x-9*x+4=0
We add all the numbers together, and all the variables
-9x+x*x+4=0
Wy multiply elements
x^2-9x+4=0
a = 1; b = -9; c = +4;
Δ = b2-4ac
Δ = -92-4·1·4
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{65}}{2*1}=\frac{9-\sqrt{65}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{65}}{2*1}=\frac{9+\sqrt{65}}{2} $
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