x+4=9/x

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Solution for x+4=9/x equation:



x+4=9/x
We move all terms to the left:
x+4-(9/x)=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x-(+9/x)+4=0
We get rid of parentheses
x-9/x+4=0
We multiply all the terms by the denominator
x*x+4*x-9=0
We add all the numbers together, and all the variables
4x+x*x-9=0
Wy multiply elements
x^2+4x-9=0
a = 1; b = 4; c = -9;
Δ = b2-4ac
Δ = 42-4·1·(-9)
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{13}}{2*1}=\frac{-4-2\sqrt{13}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{13}}{2*1}=\frac{-4+2\sqrt{13}}{2} $

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