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x+4x(5x+65)=180
We move all terms to the left:
x+4x(5x+65)-(180)=0
We multiply parentheses
20x^2+x+260x-180=0
We add all the numbers together, and all the variables
20x^2+261x-180=0
a = 20; b = 261; c = -180;
Δ = b2-4ac
Δ = 2612-4·20·(-180)
Δ = 82521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{82521}=\sqrt{9*9169}=\sqrt{9}*\sqrt{9169}=3\sqrt{9169}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(261)-3\sqrt{9169}}{2*20}=\frac{-261-3\sqrt{9169}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(261)+3\sqrt{9169}}{2*20}=\frac{-261+3\sqrt{9169}}{40} $
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