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x+4x(5x-6)=180
We move all terms to the left:
x+4x(5x-6)-(180)=0
We multiply parentheses
20x^2+x-24x-180=0
We add all the numbers together, and all the variables
20x^2-23x-180=0
a = 20; b = -23; c = -180;
Δ = b2-4ac
Δ = -232-4·20·(-180)
Δ = 14929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{14929}}{2*20}=\frac{23-\sqrt{14929}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{14929}}{2*20}=\frac{23+\sqrt{14929}}{40} $
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