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x+4x+(3/4)x=595
We move all terms to the left:
x+4x+(3/4)x-(595)=0
Domain of the equation: 4)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x+4x+(+3/4)x-595=0
We add all the numbers together, and all the variables
5x+(+3/4)x-595=0
We multiply parentheses
3x^2+5x-595=0
a = 3; b = 5; c = -595;
Δ = b2-4ac
Δ = 52-4·3·(-595)
Δ = 7165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{7165}}{2*3}=\frac{-5-\sqrt{7165}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{7165}}{2*3}=\frac{-5+\sqrt{7165}}{6} $
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