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x+4x/x-3=12/x-3
We move all terms to the left:
x+4x/x-3-(12/x-3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x-3)!=0We get rid of parentheses
x∈R
x+4x/x-12/x+3-3=0
We multiply all the terms by the denominator
x*x+4x+3*x-3*x-12=0
We add all the numbers together, and all the variables
4x+x*x-12=0
Wy multiply elements
x^2+4x-12=0
a = 1; b = 4; c = -12;
Δ = b2-4ac
Δ = 42-4·1·(-12)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*1}=\frac{-12}{2} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*1}=\frac{4}{2} =2 $
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