x+4x2=x+1x2

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Solution for x+4x2=x+1x2 equation:



x+4x^2=x+1x^2
We move all terms to the left:
x+4x^2-(x+1x^2)=0
We get rid of parentheses
4x^2-1x^2-x+x=0
We add all the numbers together, and all the variables
3x^2=0
a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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